If f integrates to g(x) + c, how does f(ax + b) integrate?
Ag(ax + b) + b + c
B(1/a) g(x + b) + c
Ca g(ax + b) + c
D(1/a) g(ax + b) + c
Answer & Solution
Correct answer: D. (1/a) g(ax + b) + c
Substituting t = ax + b gives dx = dt/a, which introduces the factor 1/a.
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