alleryStart learning →Parts applied twice to e^x sin x lead to which result?
Ae^x (sin x - cos x)/2 + c
Be^x (sin x + cos x)/2 + c
Ce^x sin x cos x/2 + c
De^x (sin x + cos x) + c
Answer & Solution
Correct answer: A. e^x (sin x - cos x)/2 + c
Applying parts twice returns the original integral, and solving gives e^x (sin x - cos x)/2.
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