alleryStart learning →Taking f = 1/x, what is the antiderivative of e^x (1/x - 1/x^2)?
Ax e^x + c
Be^x log x + c
C-e^x/x + c
De^x/x + c
Answer & Solution
Correct answer: D. e^x/x + c
With f = 1/x, f' = -1/x^2, so the integrand is e^x [f + f'] and the answer is e^x/x.
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