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Taking log x as first function, how does x log x integrate?

Ax^2 log x/2 - x^2/2 + c
B(x^2/2) log x + x^2/4 + c
C(x^2/2) log x - x^2/4 + c
D(x^2/2) log x + c
Answer & Solution
Correct answer: C. (x^2/2) log x - x^2/4 + c
By parts with log x first: (x^2/2) log x minus the integral of x/2, which is x^2/4.
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