alleryStart learning →Writing log x as 1 times log x, what is its antiderivative?
Ax log x - x + c
B(log x)^2/2 + c
C(1/x) log x + c
Dx log x + x + c
Answer & Solution
Correct answer: A. x log x - x + c
Write log x as 1 times log x and apply parts: x log x minus the integral of 1.
Keep practising Indefinite Integration
Browse all Indefinite Integration questions for MHT-CET, or explore more Mathematics topics.
Related questions
Which method suits (3x+1)/((x-1)(x+2)) when integrating?Which method finds the antiderivative of x cos x most easily?For x^2 log x by parts, which function is taken first?Dividing first, what is the integral of (x^2 + 1)/(x^2 - 1)?Factorising the quadratic x^2 - 5x + 6, what is the primitive of its reciprocal?Which is the partial fraction form for 1/((x-1)^2 (x+2))?Let 1/((x-a)(x-b)) = A/(x-a) + B/(x-b). Then A equals what?Splitting 1/(x(x+1)) into two fractions, what is its antiderivative?