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Taking x as the first function, what is the integral of x e^x?

Ax^2 e^x/2 + c
Bx e^x + c
C(x + 1) e^x + c
D(x - 1) e^x + c
Answer & Solution
Correct answer: D. (x - 1) e^x + c
Taking x as the first function gives x e^x minus the integral of e^x, which is (x - 1) e^x.
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