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With a = 3, what is the primitive of 1/(x^2 + 9)?

A(1/6) log|x - 3| + c
B(1/9) tan^-1(x/3) + c
C(1/3) tan^-1(x/3) + c
D3 tan^-1(x/3) + c
Answer & Solution
Correct answer: C. (1/3) tan^-1(x/3) + c
Using the formula with a = 3 gives (1/3) tan^-1(x/3).
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