alleryStart learning →Using x = a tan t, how does 1/sqrt(x^2 + a^2) integrate?
Alog|x + sqrt(a^2 - x^2)| + c
Blog|x^2 + a^2 + x| + c
Clog|x - sqrt(x^2 + a^2)| + c
Dlog|x + sqrt(x^2 + a^2)| + c
Answer & Solution
Correct answer: D. log|x + sqrt(x^2 + a^2)| + c
Putting x = a tan t reduces the integral to that of sec t, giving log|x + sqrt(x^2 + a^2)|.
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