Putting x = a tan t, 1/(x^2 + a^2) integrates to what?
A(1/a) tan^-1(x/a) + c
Ba tan^-1(x/a) + c
C(1/2a) log|x - a| + c
D(1/a) sin^-1(x/a) + c
Answer & Solution
Correct answer: A. (1/a) tan^-1(x/a) + c
Substituting x = a tan t gives dx = a sec^2 t dt, leaving (1/a) times t.
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