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After substituting t = log x, 1/(x log x) integrates to what?

A1/log x + c
Blog|log x| + c
Clog x + c
D(log x)^2/2 + c
Answer & Solution
Correct answer: B. log|log x| + c
Put t = log x, then the integral becomes dt/t, which is log|t| = log|log x|.
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