alleryStart learning →Find I where I = e^x/(e^x + 1) integrated over x.
Alog(e^x + 1) + c
Be^x log x + c
C1/(e^x + 1) + c
D(e^x + 1)^2/2 + c
Answer & Solution
Correct answer: A. log(e^x + 1) + c
The numerator e^x is the derivative of e^x + 1, so the integral is the log of the denominator.
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