alleryStart learning →Integrating the reciprocal 1/(3x - 2) gives which function?
A3 log|3x - 2| + c
B-1/(3x - 2)^2 + c
C(1/3) log|3x - 2| + c
Dlog|3x - 2| + c
Answer & Solution
Correct answer: C. (1/3) log|3x - 2| + c
The integral of 1/(ax+b) is (1/a) log|ax+b|, so the coefficient is one third.
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