The primitive of the cube (2x + 1)^3 is which expression?
A(2x + 1)^4/2 + c
B(2x + 1)^4/4 + c
C3(2x + 1)^2 + c
D(2x + 1)^4/8 + c
Answer & Solution
Correct answer: D. (2x + 1)^4/8 + c
By the rule for (ax+b)^n the integral is (ax+b)^(n+1) divided by a(n+1), which is 8 here.
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