Find the antiderivative of sin(2x + 3) as a function of x.
Acos(2x + 3)/2 + c
B-cos(2x + 3) + c
C-cos(2x + 3)/2 + c
D-2cos(2x + 3) + c
Answer & Solution
Correct answer: C. -cos(2x + 3)/2 + c
The integral of sin(ax+b) is -cos(ax+b)/a, and here a is 2.
Keep practising Indefinite Integration
Browse all Indefinite Integration questions for MHT-CET, or explore more Mathematics topics.
Related questions
Which method suits (3x+1)/((x-1)(x+2)) when integrating?Which method finds the antiderivative of x cos x most easily?For x^2 log x by parts, which function is taken first?Dividing first, what is the integral of (x^2 + 1)/(x^2 - 1)?Factorising the quadratic x^2 - 5x + 6, what is the primitive of its reciprocal?Which is the partial fraction form for 1/((x-1)^2 (x+2))?Let 1/((x-a)(x-b)) = A/(x-a) + B/(x-b). Then A equals what?Splitting 1/(x(x+1)) into two fractions, what is its antiderivative?