If a is a positive constant, what is the primitive of a^x?
Aa^(x+1)/(x+1) + c
Ba^x log a + c
Cx a^(x-1) + c
Da^x/log a + c
Answer & Solution
Correct answer: D. a^x/log a + c
Since d/dx of a^x equals a^x log a, dividing by log a gives the antiderivative.
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