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Tangent to y² = 8x at (2, 4)?

A2x − y + 2 = 0
Bx − y + 2 = 0
Cx − y − 2 = 0
Dx + y + 2 = 0
Answer & Solution
Correct answer: B. x − y + 2 = 0
With a = 2, yy₁ = 2a(x + x₁) gives 4y = 4(x + 2), that is x − y + 2 = 0.
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