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Ellipse relation of b, a and e?

Ab² = a²(e² − 1)
Bb² = a²(1 − e²)
Cb² = a²e²
Db² = a²(1 + e²)
Answer & Solution
Correct answer: B. b² = a²(1 − e²)
Squaring the focus-directrix relation gives c² = a²e², so b² = a² − a²e² = a²(1 − e²).
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