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Home › MHT-CET › Mathematics › Conic Sections › Focal distance of P(x₁, y₁) on y² = 4ax?

Focal distance of P(x₁, y₁) on y² = 4ax?

Ax₁ + a
Bx₁ + 2a
C2a
Dx₁ − a
Answer & Solution
Correct answer: A. x₁ + a
SP equals the distance of P from the directrix x = −a, which is x₁ + a.
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