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If $P(A)=0.3$, $P(B)=0.4$ and A, B are mutually exclusive, then $P(A\cup B)$ is:

A0.12
B0.1
C1.0
D0.7
Answer & Solution
Correct answer: D. 0.7
For mutually exclusive events, P(A∪B) = P(A)+P(B) = 0.3+0.4 = 0.7.
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