The expansion of $\sin(A+B)$ is:
A$\sin A\cos B - \cos A\sin B$
B$\cos A\cos B - \sin A\sin B$
C$\sin A\sin B + \cos A\cos B$
D$\sin A\cos B + \cos A\sin B$
Answer & Solution
Correct answer: D. $\sin A\cos B + \cos A\sin B$
Angle-sum identity: sin(A+B) = sinA cosB + cosA sinB.
Related questions
If cos θ = −1/2 and θ ∈ (π, 3π/2), then θ equals:tan(45° + θ) · tan(45° − θ) is equal to:sin 75° equals:By the law of sines in a triangle, a / sin A is equal to:The general solution of cos x = 0 is:The general solution of sin x = 0 is:If sin θ = 3/5 and θ is acute, then cos θ equals:The angle in radians for 120° is: