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The probability of getting at least one head when a coin is tossed twice is:

A$\tfrac14$
B$\tfrac34$
C$1$
D$\tfrac12$
Answer & Solution
Correct answer: B. $\tfrac34$
P(at least one head) = 1 − P(no head) = 1 − 1/4 = 3/4.
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