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When two dice are thrown, the probability that the sum of the numbers is 7 is:

A$\tfrac{1}{12}$
B$\tfrac16$
C$\tfrac{1}{9}$
D$\tfrac{7}{36}$
Answer & Solution
Correct answer: B. $\tfrac16$
Sums of 7 occur in 6 of 36 equally-likely pairs ⟹ 6/36 = 1/6.
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