If $|A| = 4$ for an invertible matrix $A$, then $|A^{-1}|$ equals:
A$16$
B$\tfrac{1}{4}$
C$1$
D$4$
Answer & Solution
Correct answer: B. $\tfrac{1}{4}$
|A⁻¹| = 1/|A| = 1/4, since |A|·|A⁻¹| = |I| = 1.
Keep practising Determinants
Browse all Determinants questions for GRE, or explore more Mathematics topics.
Related questions
An ORTHOGONAL matrix A satisfies:For the system Ax = b, if rank(A) < rank(augmented matrix A|b), the system has:By Cramer's rule, the value of x_1 in Ax = b (where A is non-singular) is:A matrix A has an INVERSE if and only if:The determinant of the 2×2 matrix [[a, b], [c, d]] equals:Matrix multiplication is:The transpose of the product (AB)^T equals:For matrices A (3×2) and B (2×4), the product AB has order: