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For matrices A (3×2) and B (2×4), the product AB has order:
A$3 × 2$ (same as the order of matrix A)
B$2 × 4$ (same as the order of matrix B)
C$3 × 4$ (rows of A, cols of B)
D$2 × 2$ (taking smallest dimensions)
Answer & Solution
Correct answer: C. $3 × 4$ (rows of A, cols of B)
AB exists if columns(A) = rows(B). Here 2 = 2 ✓. Result has order rows(A) × columns(B) = 3 × 4.
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