In a G.P. the 5th term is 81 and the 2nd term is 3. The common ratio is:
A$\tfrac{1}{3}$
B3
C9
D27
Answer & Solution
Correct answer: B. 3
We have ar⁴ = 81 and.
Then ar = 3 ⟹ r³.
That is ar = 27 ⟹ r.
So ar = 3.
Keep practising Sequences and Series
Browse all Sequences and Series questions for AP Intermediate 1st Year, or explore more Mathematics topics.
Related questions
Sum of the CUBES of the first $n$ natural numbers, $1^3 + 2^3 + \ldots + n^3$, equalsSum of the SQUARES of the first $n$ natural numbers, $1^2 + 2^2 + 3^2 + \ldots + n^2$, equSum of the first $n$ natural numbers, $1 + 2 + 3 + \ldots + n$, equalsThe Geometric Mean (GM) of $4$ and $9$ isThe Arithmetic Mean (AM) of two positive numbers $a$ and $b$ isThe sum to INFINITY of the GP $1 + 1/2 + 1/4 + 1/8 + \ldots$ isThe sum of the first $n$ terms of a GP with first term $a$ and common ratio $r \neq 1$ isThe $n^\text{th}$ term of a Geometric Progression (GP) with first term $a$ and common rati