A lift descends with a downward acceleration equal to g. The apparent weight of a passenger standing inside is:
Azero
Btwice mg
Cequal to mg
Dhalf of mg
Answer & Solution
Correct answer: A. zero
Apparent weight N = m(g − a). With downward acceleration a = g, N = 0 — the passenger is in free fall and feels weightless.
Related questions
A constant force of 6 N acts for 4 s on a 2 kg body initially at rest. The kinetic energy A stone of mass 0.5 kg is whirled in a horizontal circle of radius 1 m at constant angularA car of mass 1000 kg accelerates from rest to 20 m s⁻¹ in 5 s on a level road. The net hoA man weighing 50 kg jumps off a stationary boat of mass 250 kg into water with a horizontNewton's third law states that 'action and reaction are equal and opposite'. The most accuTwo identical billiard balls strike a smooth rigid wall with equal speeds u. Ball A strikeA force F acts on a particle making an angle θ with its instantaneous velocity. The componA cricketer draws his hands back while catching a fast ball. The physical reason is that: