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When an electron drops from energy Ei to a lower Ef, what is the photon frequency?
Ah/(Ei - Ef)
B(Ei - Ef)/h
CEi Ef/h
D(Ei + Ef)/h
Answer & Solution
Correct answer: B. (Ei - Ef)/h
Bohr's third postulate sets the photon energy hν equal to the difference of the two level energies.
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