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A reflector section is y² = 16x cut off by x = 4. Find its area
A128/3 sq units
B32 sq units
C64/3 sq units
D256/3 sq units
Answer & Solution
Correct answer: A. 128/3 sq units
Twice the integral of 4√x from 0 to 4 is 8 x (2/3) x 8 = 128/3.
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