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What is the area under the parabola y = x² over the symmetric interval [-2, 2]?
A16/3 sq units
B4 sq units
C8 sq units
D8/3 sq units
Answer & Solution
Correct answer: A. 16/3 sq units
The integral of x² over -2 to 2 is 2 x 8/3 = 16/3.
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