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The parabola x² = 4y and the line y = x enclose what area?
A16/3 sq units
B4 sq units
C8/3 sq units
D4/3 sq units
Answer & Solution
Correct answer: C. 8/3 sq units
They meet at x = 0 and 4; the integral of (x - x²/4) is 8 - 16/3 = 8/3.
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