Home › CBSE Class 12 (Commerce) › Mathematics › Application of Integrals › Area of the region enclosed by 4x² + y² = 36 is
Area of the region enclosed by 4x² + y² = 36 is
A36π sq units
B9π sq units
C6π sq units
D18π sq units
Answer & Solution
Correct answer: D. 18π sq units
Dividing by 36 gives x²/9 + y²/36 = 1, so a = 3, b = 6 and the area is πab = 18π.
Related questions
Area between the x-axis and the parabola y = 4x - x² isThe smaller part of x² + y² = a² cut off by the line x = a/√2 has areaWhat is the area under the parabola y = x² over the symmetric interval [-2, 2]?The area under y = f(x) from x = a to x = b is obtained by addingElementary geometry formulae are inadequate for finding areas that areThe V-shaped curve y = |x| over [-3, 3] and the x-axis enclose how much area?A circle with centre (2, 0) and equation (x - 2)² + y² = 9 bounds an area ofThe area under y = √(a² - x²) for 0 ≤ x ≤ a is