Home › CBSE Class 12 (Commerce) › Mathematics › Application of Integrals › The parabola y = x² and the chord y = 2x meet at…
The parabola y = x² and the chord y = 2x meet at (0, 0) and (2, 4). Find the area between
A8/3 sq units
B2/3 sq units
C4 sq units
D4/3 sq units
Answer & Solution
Correct answer: D. 4/3 sq units
They meet at x = 0 and 2; the integral of (2x - x²) is 4 - 8/3 = 4/3.
Related questions
Area between the x-axis and the parabola y = 4x - x² isThe smaller part of x² + y² = a² cut off by the line x = a/√2 has areaWhat is the area under the parabola y = x² over the symmetric interval [-2, 2]?The area under y = f(x) from x = a to x = b is obtained by addingElementary geometry formulae are inadequate for finding areas that areThe V-shaped curve y = |x| over [-3, 3] and the x-axis enclose how much area?A circle with centre (2, 0) and equation (x - 2)² + y² = 9 bounds an area ofThe area under y = √(a² - x²) for 0 ≤ x ≤ a is