alleryIn a standing wave represented by $y=2A\sin kx\cos\omega t$, the amplitude of a particle at position $x$ is
A$A$
B$2A\cos\omega t$
C$2A\sin kx$
D$\omega/k$
Answer & Solution
Correct answer: C. $2A\sin kx$
For a standing wave, the displacement has the form $(\text{position factor})\times(\text{time factor})$.
The amplitude depends only on position, so here it is $2A\sin kx$ in magnitude.
**Hence option C is correct.**
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