Nitrobenzene gives hydroxylamine by- 
A$Sn / HCl$
B$Zn / NaOH$
C$H_{2} / Pd - C$
D$Zn / NH_{4}Cl$
Answer & Solution
Correct answer: D. $Zn / NH_{4}Cl$
The product formed on partial reduction of nitrobenzene depends on the medium. $Zn/NH_4Cl$ in neutral medium reduces nitrobenzene to phenylhydroxylamine. In contrast, stronger acidic or catalytic hydrogenation conditions generally reduce it further to aniline.
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