2.5 F of electricity are passed through a $\mathrm{CuSO_4}$ solution. The number of gram equivalent of Cu deposited on anode is

In electrolysis of $\mathrm{CuSO_4}$, copper is deposited at the cathode, not at the anode. At the anode, oxidation occurs so no copper gets deposited there. Therefore, the gram equivalent of copper deposited on anode is $0$. Among the options, $\mathrm{Zero}$ matches this result.