The approximate magnifying power of a compound microscope is given by
A$m=\dfrac{f_o}{f_e}$
B$m=\dfrac{L}{f_e}\times\dfrac{D}{f_o}$
C$m=\dfrac{L}{f_o}\times\dfrac{D}{f_e}$
D$m=\dfrac{D}{L}\times\dfrac{f_o}{f_e}$
Answer & Solution
Correct answer: C. $m=\dfrac{L}{f_o}\times\dfrac{D}{f_e}$
For a compound microscope, the approximate magnifying power is $m=(L/f_o)\times(D/f_e)$, where $L$ is the distance between the focal points of the objective and eyepiece, $f_o$ is the focal length of the objective, and $f_e$ is the focal length of the eyepiece. Option A is the telescope formula, not the microscope formula.
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