A convex lens forms a real image at $60$ cm on one side of an object placed $20$ cm in front of it. Find the focal length of the lens.
A$10$ cm
B$12$ cm
C$15$ cm
D$20$ cm
Answer & Solution
Correct answer: C. $15$ cm
Lens formula: $\dfrac{1}{f} = \dfrac{1}{v} - \dfrac{1}{u}$. Sign convention: $u = -20$ cm (object on the left), $v = +60$ cm (real image on the right).
We have $\dfrac{1}{f} = \dfrac{1}{60} - \dfrac{1}{-20}$.
That is $\dfrac{1}{f} = \dfrac{1}{60} + \dfrac{3}{60}$.
That is $\dfrac{1}{f} = \dfrac{4}{60}$.
So $\dfrac{1}{f} = \dfrac{1}{15}$.
So $f = 15$ cm.
**Trap.** Forgetting the sign on $u$ gives $\dfrac{1}{f} = \dfrac{1}{60} - \dfrac{1}{20} = -\dfrac{1}{30}$, leading to a negative $f$ — that's how option B
(12) or A (10) creeps in.
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