Which of the following is **NOT** a possible set of quantum numbers for a 3d electron?
A$(3, 1, +1, -1/2)$
B$(3, 2, -2, -1/2)$
C$(3, 2, 0, +1/2)$
D$(3, 2, +2, +1/2)$
Answer & Solution
Correct answer: A. $(3, 1, +1, -1/2)$
For 3d, $n=3, l=2$. Option A has $l=1$, which would be a 3p orbital, not 3d. Options B–D all satisfy $(n=3, l=2)$ with valid $m_l$ and $m_s$.
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