How many *angular* nodes does a $3d$ orbital have?
A$1$
B$2$
C$0$
D$3$
Answer & Solution
Correct answer: B. $2$
Angular nodes = $l$. For d ($l=2$): 2 angular nodes. Total nodes = $n - 1 = 2$; radial nodes = $n - l - 1 = 0$. A 3d orbital has 2 angular nodes and no radial nodes.
Related questions
Calcium-40 (Z=20, A=40) and Argon-40 (Z=18, A=40) are best described as:Atoms of the SAME element with DIFFERENT mass numbers are called:An atom of chlorine has atomic number Z = 17 and mass number A = 37. The number of neutronThe atomic number (Z) of an element is equal to the:The neutron was discovered by:Bohr's model of the atom fixed Rutherford's instability problem by proposing that electronRutherford's gold foil experiment concluded that most of the atom is:The Rydberg constant for hydrogen, in SI units, is