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How many *angular* nodes does a $3d$ orbital have?
A$1$
B$2$
C$0$
D$3$
Answer & Solution
Correct answer: B. $2$
Angular nodes = $l$. For d ($l=2$): 2 angular nodes. Total nodes = $n - 1 = 2$; radial nodes = $n - l - 1 = 0$. A 3d orbital has 2 angular nodes and no radial nodes.
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