For orbital quantum number $l$, the magnetic quantum number $m_l$ takes values
A$\pm 1/2$
B$1, 2, \ldots, l$
C$0, 1, 2, \ldots, l$
D$-l, -l+1, \ldots, 0, \ldots, l-1, l$
Answer & Solution
Correct answer: D. $-l, -l+1, \ldots, 0, \ldots, l-1, l$
$m_l$ takes $2l+1$ values: $-l, -l+1, \ldots, 0, \ldots, +l$. So p ($l=1$) has 3 orientations ($-1, 0, +1$ = $p_x, p_y, p_z$); d ($l=2$) has 5; etc.
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