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The longest wavelength line in the Lyman series of hydrogen corresponds to the transition
A$n = 2 \to n = 3$
B$n = \infty \to n = 1$
C$n = 2 \to n = 1$
D$n = 3 \to n = 1$
Answer & Solution
Correct answer: C. $n = 2 \to n = 1$
Longest wavelength = smallest energy gap in the series. For Lyman ($n_{final} = 1$), the smallest gap is between $n=2$ and $n=1$.
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