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WBJEE Halogen Derivatives — practice questions

Explore 12 free Halogen Derivatives questions in WBJEE Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Halogen Derivatives questions and exercises with answers

Showing questions 1–12 of 12.

Worked practice questions

In an **alkyl halide (haloalkane)**, the halogen is bonded to a:

  1. sp³-hybridised carbon (saturated)
  2. sp²-hybridised carbon (double-bond carbon)
  3. sp-hybridised carbon (triple-bond carbon)
  4. Aromatic ring carbon
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Correct answer: A. sp³-hybridised carbon (saturated)

Alkyl halides have X bonded to sp³ C in a saturated chain. Vinyl halides (sp²), haloalkynes (sp), and aryl halides (aromatic sp²) are different categories with very different reactivity.

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An **allylic halide** has the halogen bonded to:

  1. A carbon directly part of C=C double bond
  2. A sp³ carbon adjacent to (next to) a C=C double bond
  3. An aromatic carbon
  4. A sp carbon
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Correct answer: B. A sp³ carbon adjacent to (next to) a C=C double bond

Allylic position = the sp³ carbon NEXT to a double bond. **Example:** CH₂=CH-CH₂-X. Different from vinyl halides where X is ON the double-bond carbon (CH₂=CH-X).

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Among haloalkanes, the order of C–X **bond length** is:

  1. C-F > C-Cl > C-Br > C-I
  2. C-I > C-Br > C-Cl > C-F (larger halogen = longer bond)
  3. All same
  4. C-Cl > C-Br > C-F > C-I
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Correct answer: B. C-I > C-Br > C-Cl > C-F (larger halogen = longer bond)

Halogen size increases F < Cl < Br < I. Larger halogen p-orbital ⇒ longer C–X bond. Bond enthalpy decreases in the same direction. C–I bond is the weakest, easiest to break.

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