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Among haloalkanes, the order of C–X **bond length** is:
AC-F > C-Cl > C-Br > C-I
BC-I > C-Br > C-Cl > C-F (larger halogen = longer bond)
CAll same
DC-Cl > C-Br > C-F > C-I
Answer & Solution
Correct answer: B. C-I > C-Br > C-Cl > C-F (larger halogen = longer bond)
Halogen size increases F < Cl < Br < I. Larger halogen p-orbital ⇒ longer C–X bond. Bond enthalpy decreases in the same direction. C–I bond is the weakest, easiest to break.
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