Among haloalkanes, the order of C–X **bond length** is:
- C-F > C-Cl > C-Br > C-I
- C-I > C-Br > C-Cl > C-F (larger halogen = longer bond)
- All same
- C-Cl > C-Br > C-F > C-I
Show answer and solution
Correct answer: B. C-I > C-Br > C-Cl > C-F (larger halogen = longer bond)
Halogen size increases F < Cl < Br < I. Larger halogen p-orbital ⇒ longer C–X bond.
Bond enthalpy decreases in the same direction.
C–I bond is the weakest, easiest to break.