A simple pendulum of period $T$ on Earth is taken to the Moon where $g_{moon} = g/6$. Its new period is:
- $T/\sqrt 6$
- $T\sqrt 6$
- $T/6$
- $6T$
Show answer and solution
Correct answer: B. $T\sqrt 6$
$T \propto 1/\sqrt g$.
Moon's g is g/6, so new period = $T \sqrt 6 \approx 2.45 T$.
Pendulum oscillates 2.45× slower on Moon.