A simple pendulum of period $T$ on Earth is taken to the Moon where $g_{moon} = g/6$. Its new period is:
A$T/\sqrt 6$
B$T\sqrt 6$
C$T/6$
D$6T$
Answer & Solution
Correct answer: B. $T\sqrt 6$
$T \propto 1/\sqrt g$. Moon's g is g/6, so new period = $T \sqrt 6 \approx 2.45 T$. Pendulum oscillates 2.45× slower on Moon.
Related questions
Two waves of slightly different frequencies but equal amplitude combine to produce:Two identical waves arrive crest on trough, so the amplitude of the result is:Two identical waves arrive crest on crest, so the amplitude of the result is:A wave whose disturbance is parallel to its direction of travel is:A wave whose disturbance is perpendicular to its direction of travel is:The distance between adjacent identical parts of a wave is its:Driving a system at its natural frequency, so the amplitude grows large, produces:A system that reaches equilibrium quickly but oscillates about it is described as: