alleryA simple pendulum of period $T$ on Earth is taken to the Moon where $g_{moon} = g/6$. Its new period is:
A$T/\sqrt 6$
B$T\sqrt 6$
C$T/6$
D$6T$
Answer & Solution
Correct answer: B. $T\sqrt 6$
$T \propto 1/\sqrt g$.
Moon's g is g/6, so new period = $T \sqrt 6 \approx 2.45 T$.
Pendulum oscillates 2.45× slower on Moon.
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