The pressure at the **top of a column of water** open to atmosphere is approximately:
- $10^5$ Pa (atmospheric pressure)
- Zero
- $10^7$ Pa
- Cannot be determined
Show answer and solution
Correct answer: A. $10^5$ Pa (atmospheric pressure)
Surface of an open water body is at atmospheric pressure $p_0 \approx 1.013 \times 10^5$ Pa.
**Pressure increases with depth:** $p = p_0 + h\rho g$.