The pressure at the **top of a column of water** open to atmosphere is approximately:
A$10^5$ Pa (atmospheric pressure)
BZero
C$10^7$ Pa
DCannot be determined
Answer & Solution
Correct answer: A. $10^5$ Pa (atmospheric pressure)
Surface of an open water body is at atmospheric pressure $p_0 \approx 1.013 \times 10^5$ Pa. Pressure increases with depth: $p = p_0 + h\rho g$.
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