The **chain rule** states $\dfrac{dy}{dx}$ for $y = f(g(x))$ is:
- $f'(g(x)) + g'(x)$
- $f'(g(x)) \cdot g'(x)$
- $f'(x) \cdot g'(x)$
- $f'(g(x))$
Show answer and solution
Correct answer: B. $f'(g(x)) \cdot g'(x)$
**Chain rule:** $dy/dx = f'(g(x)) \cdot g'(x)$.
Differentiate outer function evaluated at inner, then multiply by derivative of inner.