alleryThe **chain rule** states $\dfrac{dy}{dx}$ for $y = f(g(x))$ is:
A$f'(g(x)) + g'(x)$
B$f'(g(x)) \cdot g'(x)$
C$f'(x) \cdot g'(x)$
D$f'(g(x))$
Answer & Solution
Correct answer: B. $f'(g(x)) \cdot g'(x)$
**Chain rule:** $dy/dx = f'(g(x)) \cdot g'(x)$.
Differentiate outer function evaluated at inner, then multiply by derivative of inner.
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